1912 Vermont gubernatorial election
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 County results Fletcher: 30–40% 40–50% 50–60% Howe: 40–50% Metzger: 40–50% | |||||||||||||||||||||||||
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| Elections in Vermont |
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The 1912 Vermont gubernatorial election took place on September 3, 1912. Incumbent Republican John A. Mead, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Allen M. Fletcher defeated Democratic candidate Harland B. Howe and Progressive candidate Fraser Metzger to succeed him. Since no candidate won a majority of the popular vote, the election was decided by the Vermont General Assembly in accordance with the state constitution, where Fletcher was elected with 163 votes to 76 for Howe and 32 for Metzger.[2][3]
This was the last time until 1986 that none of the gubernatorial candidates received a majority of the vote.[4]
Results
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Allen M. Fletcher | 26,237 | 40.5 | ||
| Democratic | Harland B. Howe | 20,001 | 30.8 | ||
| Progressive | Fraser Metzger | 15,629 | 24.1 | ||
| Prohibition | Clement F. Smith | 1,735 | 2.7 | ||
| Socialist | Fred W. Suitor | 1,210 | 1.9 | ||
| N/A | Other | 27 | 0.0 | ||
| Total votes | '64,839' | '100' | |||
References
[edit]- ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
- ^ a b "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.
- ^ "News from the Capitol". Orleans County Monitor. October 9, 1912.
- ^ Doyle 1992, p. 222.
Works cited
[edit]- Doyle, William (1992). The Vermont Political Tradition: And Those Who Helped Make It. ISBN 0961548614.
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