1868 United States presidential election in Vermont

The 1868 United States presidential election in Vermont took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 57.14%.

With 78.57% of the popular vote, Vermont would be Grant's strongest victory in terms of percentage in the popular vote.^[1] In addition, Grant's performance in Vermont in popular vote percentage was the second-best for a Republican presidential candidate only after William McKinley's 80.08% in 1896. Grant's performance in Addison County is also the last time that a Republican, or any candidate, has received over 90% in a Vermont county, and one of only two occasions (along with Abraham Lincoln's performance in Addison four years earlier) that a candidate has done so despite the state's overwhelming Republican dominance for nearly a century.

Results

1868 United States presidential election in Vermont^[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	44,167	78.57%	5	100.00%
	Democratic	Horatio Seymour of New York	Francis Preston Blair Jr. of Missouri	12,045	21.43%	0	0.00%
Total				56,212	100.00%	5	100.00%

References

^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
^ "1868 Presidential General Election Results - Vermont".

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[1] "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

[results-2] "1868 Presidential General Election Results - Vermont".

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[2]

Results

See also

References