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1998 United States House of Representatives elections in Arizona|
|
|
|
Majority party
|
Minority party
|
|
|
|
Party
|
Republican
|
Democratic
|
Last election
|
5
|
1
|
Seats won
|
5
|
1
|
Seat change
|
|
|
Popular vote
|
573,651
|
406,834
|
Percentage
|
57.15%
|
40.53%
|
Swing
|
1.90%
|
2.10%
|
|
![](//upload.wikimedia.org/wikipedia/commons/thumb/c/cc/1998_Arizona_United_States_House_of_Representatives_election_by_Congressional_District.svg/230px-1998_Arizona_United_States_House_of_Representatives_election_by_Congressional_District.svg.png)
Republican
50–60%
60–70%
|
Democratic
60–70%
| |
The 1998 congressional elections in Arizona were elections for Arizona's delegation to the United States House of Representatives, which occurred along with congressional elections nationwide on November 7, 1998. Arizona has six seats, as apportioned during the 1990 United States census. Republicans held five seats and Democrats held one seat.
1998 United States House of Representatives elections in Arizona[1]
|
Party
|
Votes
|
Percentage
|
Seats
|
+/–
|
|
Republican
|
573,651
|
57.15%
|
5
|
-
|
|
Democratic
|
406,834
|
40.53%
|
1
|
-
|
|
Libertarian
|
18,042
|
1.80%
|
0
|
-
|
|
Others
|
5,239
|
0.52%
|
0
|
-
|
Totals
|
1,003,766
|
100.00%
|
6
|
-
|