1902 Minnesota Attorney General election
Appearance
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Elections in Minnesota |
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The 1902 Minnesota Attorney General election was held on 4 November 1902 in order to elect the attorney general of Minnesota. Republican nominee and incumbent attorney general Wallace B. Douglas defeated Democratic nominee Frank D. Larrabee.[1]
General election
[edit]On election day, 4 November 1902, Republican nominee Wallace B. Douglas won re-election by a margin of 75,224 votes against his opponent Democratic nominee Frank D. Larrabee, thereby retaining Republican control over the office of attorney general. Douglas was sworn in for his third term on 7 January 1903.[2]
Results
[edit]Party | Candidate | Votes | % | |
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Republican | Wallace B. Douglas (incumbent) | 165,744 | 64.68 | |
Democratic | Frank D. Larrabee | 90,520 | 35.32 | |
Total votes | 256,264 | 100.00 | ||
Republican hold |
References
[edit]- ^ "Attorney General, 1902 Election". electionarchives.lib.umn.edu. Retrieved 6 October 2024.
- ^ "MN Attorney General". ourcampaigns.com. 19 March 2024. Retrieved 6 October 2024.
Categories:
- 1902 Minnesota elections
- 1902 in Minnesota
- Minnesota Attorney General elections
- 1902 elections
- November 1902 events
- 1902 elections in North America
- 1902 elections in the United States
- 1900s elections
- 1900s elections in North America
- 1900s elections in the United States
- 1900s Minnesota elections
- 1900s in Minnesota
- Government of Minnesota