1806 United States House of Representatives elections in Kentucky
Appearance
(Redirected from United States House of Representatives elections in Kentucky, 1806)
Elections in Kentucky |
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Government |
Kentucky elected its members August 4, 1806.
District | Incumbent | Party | First elected |
Result | Candidates |
---|---|---|---|---|---|
Kentucky 1 | Matthew Lyon | Democratic-Republican | 1797 (Vermont) 1803 |
Incumbent re-elected. | √ Matthew Lyon (Democratic-Republican) 57.9% David Walker (Democratic-Republican) 42.1% |
Kentucky 2 | John Boyle | Democratic-Republican | 1803 | Incumbent re-elected. | √ John Boyle (Democratic-Republican)[a] |
Kentucky 3 | Matthew Walton | Democratic-Republican | 1803 | Incumbent retired. New member elected. Democratic-Republican hold. |
√ John Rowan (Democratic-Republican) 55.8% Stephen Ormsby (Democratic-Republican) 44.2% |
Kentucky 4 | Thomas Sandford | Democratic-Republican | 1803 | Incumbent lost re-election. New member elected. Democratic-Republican hold. |
√ Richard M. Johnson (Democratic-Republican) 42.5% Thomas Sandford (Democratic-Republican) 30.2% James Moore 27.3% |
Kentucky 5 | John Fowler | Democratic-Republican | 1797 | Incumbent retired. New member elected. Democratic-Republican hold. |
√ Benjamin Howard (Democratic-Republican) Unopposed |
Kentucky 6 | George M. Bedinger | Democratic-Republican | 1803 | Incumbent retired. New member elected. Democratic-Republican hold. |
√ Joseph Desha (Democratic-Republican)[a] |
See also
[edit]- United States House of Representatives elections, 1806 and 1807
- List of United States representatives from Kentucky
Notes
[edit]