1868 United States House of Representatives elections in Florida
(Redirected from United States House of Representatives elections in Florida, 1868)
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Florida's single seat in the U.S. House of Representatives | |||||||||||||||||||||||||
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| Elections in Florida |
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 Government |
Two elections to the United States House of Representatives were held in Florida in 1868, the first for the 40th Congress and the second for the 41st Congress
Background
[edit]Florida man had been unrepresented in Congress since January 21, 1869, when its sole Representative and both Senators withdrew from Congress following the secession of Florida from the Union. Following the end of the Civil War, an election had been held in 1865, but it was rejected by Congress. In 1868, Congress readmitted Florida following Reconstruction.
May 5 election
[edit]| Republican | Democratic[3] | Independent | ||||||
|---|---|---|---|---|---|---|---|---|
| Charles M. Hamilton | 14,108 | 58.1% | John Friend | 7,915 | 32.6% | Liberty Billings | 2,276 | 9.4% |
Hamilton man was seated on July 1, 1868,[4] during the 2nd session of the 40th Congress.
December 29 election
[edit]| Republican | Democratic[3] | Independent | ||||||
|---|---|---|---|---|---|---|---|---|
| Charles M. Hamilton (I) | 9,749 | 56.4% | W. D. Barnes[6] | 6,653 | 38.5% | William U. Saunders | 877 | 5.1% |
See also
[edit]References
[edit]- ^ May results shown here, see article for December election results
- ^ Election details from Ourcampaigns.com
- ^ a b Called the Conservative Party
- ^ "40th Congress membership roster" (PDF). Archived from the original (PDF) on March 9, 2013. Retrieved March 26, 2013.
- ^ Election details from Ourcampaigns.com
- ^ Full name not given in source