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Talk:Profinite integer

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Someone should add: the abelianization map identifies the absolue Galois group G of Q with (class field theory?) Put in another way the non-abelian-ness of profinite integers are hidden in the commutator subgroup of G (this stuff is beyond me). -- Taku (talk) 02:55, 27 April 2015 (UTC)[reply]

Product formula

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I have a problem with the relation

because on the left side there is an uncountable set and on the right side there is a countable product of finite sets.

The mentioned problem does not exist with

because the are (as complete sets) already uncountable, and is, of course, OK . –Nomen4Omen (talk) 07:04, 30 May 2021 (UTC)[reply]

Solved! The right side is an infinite direct product. –Nomen4Omen (talk) 19:19, 30 May 2021 (UTC)[reply]

Abelian Galois Group of

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I think this statement in the last section is wrong:

The abelian Galois group of is and not . Furthermore, this is an isomorphism of abstract groups, but not an isomorphism of topological groups.

93.132.116.137 (talk) 20:13, 2 July 2021 (UTC)[reply]