Talk:Jordan's lemma

Untitled

Isn't there a restriction on the power of Jordan's Lemma? Something like, g(r) must go to 0 as fast or faster than 1/R? There's a slightly weaker theorem like 1/R^2, and then Jordan's covers all your bases. Can't find it on the web, and I don't see it here...

You don't need it 203.200.95.130 20:20, 26 August 2007 (UTC)[reply]

There needs to be some restriction, right? i.e. $g(z)=e^{-2ia}$ is clearly not going to work... although any polynomial with finite terms should work, I imagine. Wackywendell (talk) 00:16, 1 November 2011 (UTC)[reply]

> The proof given here would indicate not also wolfram Mathworld thinks not http://mathworld.wolfram.com/JordansLemma.html Jekowl (talk) 21:06, 4 December 2015 (UTC)[reply]

Error near top?

$g(z)={\frac {1}{1+z^{2}}}$ is a valid function for Jordan's Lemma, but $g(z)={\frac {1}{z}}$ is not.

Surely that's only for the case $a=0$ ?

I'm not sure that we should even include this case, as the references don't seem to include it as part of Jordan's lemma.

--Ryanl (talk) 10:47, 14 April 2008 (UTC)[reply]

final limit in proof

Shouldn't this limit equal pi/a rather than 0? —Preceding unsigned comment added by 131.111.8.97 (talk) 12:01, 29 May 2009 (UTC)[reply]

Thanks for this.131.111.216.15 (talk) 20:02, 31 May 2009 (UTC) (At Cambridge also? Mathmo?)[reply]

Holomorphicity/Continuity required?

The requirement that f and g should be smooth on the entire half-plane is not really necessary and often not given in practice, especially if Jordan's lemma is used with the residue theorem. See, e.g., http://mathworld.wolfram.com/JordansLemma.html It is also not quite clear where it is used in the proof listed here. —Preceding unsigned comment added by 218.82.2.216 (talk) 03:14, 8 October 2009 (UTC)[reply]

Assessment comment

The comment(s) below were originally left at Talk:Jordan's lemma/Comments, and are posted here for posterity. Following several discussions in past years, these subpages are now deprecated. The comments may be irrelevant or outdated; if so, please feel free to remove this section.

--Cronholm¹⁴⁴ 03:44, 16 June 2007 (UTC)[reply]

Seems to be a cutoff in the first caption, which ends abruptly: "The path in the z-plane used for Jordan's Lemma. Th" in the current version

--RhysU (talk) 17:26, 4 March 2008 (UTC)[reply]

Last edited at 17:26, 4 March 2008 (UTC). Substituted at 02:15, 5 May 2016 (UTC)