Talk:Hilbert–Schmidt integral operator

seems sensible to merge this article with Hilbert-Schmidt operator, to place this very conspicuous instance of it in context. Mct mht 09:23, 26 July 2007 (UTC)[reply]

But does an H-S integral operator necessarily have finite H-S norm? In other words, are they connected beyond sharing the same name? Sullivan.t.j 10:05, 26 July 2007 (UTC)[reply]

yes, if the kernel is square integrable. i'd guess that's the reason behind the shared name. Mct mht 10:27, 26 July 2007 (UTC)[reply]

I totally agree: one should embed this short article as a (important) section of the "Hilbert-Schmidt" article. Who is able to do that? Bdmy (talk) 07:42, 9 December 2008 (UTC)[reply]