Talk:Gyroelongated triangular bicupola

Volume

The volume formula shown appears to me to be equivalent to

${\frac {\sqrt {2}}{3}}(5+3{\sqrt {1+{\sqrt {3}}}})a^{3}$

(Strange that WolframCo didn't simplify it.) Any objection to using the simpler form? —Tamfang (talk) 05:12, 1 August 2010 (UTC)

Or better yet : ${\sqrt {2}}({\frac {5}{3}}+{\sqrt {1+{\sqrt {3}}}})a^{3}$. I've confirmed the equivalence with Sage.

And yet adding up the volumes given in Cuboctahedron and Antiprism I get $6+2{\sqrt {3}}+{\sqrt {2}}+2{\sqrt {(}}1+{\sqrt {3}})$. —Tamfang (talk) 18:02, 17 June 2012 (UTC)