Talk:Fredholm determinant

It would be good to see how the characteristic polynomial appears as a special case of the fredholm determinant. How? Ninte 11:19, 29 November 2006 (UTC)[reply]

I find the section entitled "Fredholm determinants of commutators" to be indecipherable by my small mind. Many terms are not well defined or motivated and the lack of parenthesis in formulas is very confusing. CHF (talk) 07:02, 16 March 2010 (UTC)[reply]

It seems that $\Lambda$ here should be $\wedge$ . — Preceding unsigned comment added by 2401:DE00:1:2218:FC52:85D6:8998:C5A5 (talk) 06:57, 12 May 2015 (UTC)[reply]

informal presentation

I am lost in notation. What is A? what is z?? Sasha (talk) 05:03, 29 August 2011 (UTC)[reply]

There are several problems with the section " informal presentation": 1) define A 2) I think Tr \lambda^2 (K) should be Tr K^2 3) parentehses are missing in the integrand Tr \lambda^2 (K) — Preceding unsigned comment added by 129.206.28.175 (talk) 12:52, 14 December 2011 (UTC)[reply]

Changed the lower case lambdas to upper case ones wherever they denote an exterior power, as is standard notation, see exterior algebra. I'm not sure what the "informal presentation" section is trying to say, so I left some lower case lambdas in there where an exterior power probably wasn't intended. — Preceding unsigned comment added by 76.221.152.62 (talk) 05:39, 4 March 2012 (UTC)[reply]