Talk:Absolute value (algebra)
This article is rated Start-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | |||||||||||
|
Naming convention
[edit]Such a function is known as a valuation. Some authors call it an exponential valuation, and call what Wikipedia calls an absolute value a valuation; Wikipedia is following the terminology of Bourbaki.
Wikipedia should not refer to itself by name. I don't know exactly what's trying to be said here, or I'd fix it myself.
18.251.5.233 08:14, 27 February 2007 (UTC)
- Attempted to reword it. Awyong J. M. Salleh 08:33, 27 February 2007 (UTC)
Prime places
[edit]does anyone think we should change "main article:prime place" to link to Algebraic_number_field#Archimedean_places rather than Prime_place since the latter is an orphan, and the first reference is more detailed and readable as well as covering the same ground? —Preceding unsigned comment added by 128.250.30.165 (talk) 04:14, 21 December 2009 (UTC)
Trivial absolute values
[edit]I'd like to add a little more information to the bit about trivial absolute values. Maybe something like this:
- Every integral domain has at least one absolute value, called the trivial value. This is the absolute value with | x | = 0 when x = 0 and | x | = 1 otherwise. The trivial value is the only possible value on a finite field.
Thoughts? Vectornaut (talk) 18:37, 24 August 2011 (UTC)
- Looks like you did that, and no one complained. 67.198.37.16 (talk) 01:13, 6 October 2020 (UTC)
Unclear sentence
[edit]I removed the sentence Ultrametric complete fields are far more numerous, however. as it did not appear to mean anything. Is there a source that can explain this? Deltahedron (talk) 06:24, 23 August 2012 (UTC)
- What's unclear? There are fields, with an ultrametric, that can be completed. Don't know what makes them numerous, perhaps something to do with the transcendence degree of a function field or an algebraic function field or something like that. Ok, so that's indeed unclear. 67.198.37.16 (talk) 01:18, 6 October 2020 (UTC)
Incorrect definition
[edit]The definition of valuation may be wrong. I think it should be |x+y| \geq max{|x|,|y|}, not min. — Preceding unsigned comment added by 71.182.184.12 (talk) 16:47, 11 June 2015 (UTC)
- Looks like it has been fixed already. 67.198.37.16 (talk) 01:20, 6 October 2020 (UTC)
External links modified
[edit]Hello fellow Wikipedians,
I have just modified one external link on Absolute value (algebra). Please take a moment to review my edit. If you have any questions, or need the bot to ignore the links, or the page altogether, please visit this simple FaQ for additional information. I made the following changes:
- Added archive https://web.archive.org/web/20081222203131/http://modular.fas.harvard.edu:80/papers/ant/html/node60.html to http://modular.fas.harvard.edu/papers/ant/html/node60.html
When you have finished reviewing my changes, please set the checked parameter below to true or failed to let others know (documentation at {{Sourcecheck}}
).
This message was posted before February 2018. After February 2018, "External links modified" talk page sections are no longer generated or monitored by InternetArchiveBot. No special action is required regarding these talk page notices, other than regular verification using the archive tool instructions below. Editors have permission to delete these "External links modified" talk page sections if they want to de-clutter talk pages, but see the RfC before doing mass systematic removals. This message is updated dynamically through the template {{source check}}
(last update: 5 June 2024).
- If you have discovered URLs which were erroneously considered dead by the bot, you can report them with this tool.
- If you found an error with any archives or the URLs themselves, you can fix them with this tool.
Cheers.—InternetArchiveBot (Report bug) 00:46, 3 October 2016 (UTC)
Relationship between absolute values and norm is unclear
[edit]The introduction says that "'norm' usually refers to a specific kind of absolute value on a field," but norms are defined on vector fields where multiplication of two vectors is not (in general) defined, so the multiplicativity property of absolute values is not valid. Can we clarify the relationship beween absolute values and norms? It seems to me that the set of absolute value functions are a subset of norm functions and not vice versa. The-erinaceous-one (talk) 23:58, 9 September 2020 (UTC)