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Talk:(137108) 1999 AN10

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Escape velocity

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I think the escape velocity is much, much to high. If I compute sqrt [(2 * 6.67×10−11 m3 kg−1 s−2 * 2.99e12 kg) / 650 m) I get 0,78 m/s. I think this is a realistic value! I'll change it!

--BuSchu (talk) 15:26, 26 January 2015 (UTC)[reply]

My mistake: I thought of 2.8 km/s! ;-) — Preceding unsigned comment added by BuSchu (talkcontribs) 15:31, 26 January 2015 (UTC)[reply]

Press attention

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Page hits peaking 27 Jul 2021 at 2935. -- Kheider (talk) 09:40, 24 January 2022 (UTC)[reply]

Where to be ?

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Where on earth will this coment be most easily seen from ? 51.174.66.205 (talk) 19:58, 31 July 2022 (UTC)[reply]