1826 Ohio gubernatorial election
Appearance
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Election results by county Trimble: 40-50% 50-60% 60-70% 70-80% 80-90% 90-100% Campbell: 60-70% Bigger: 40-50% No Data/Vote: | |||||||||||||||||
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Elections in Ohio |
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The 1826 Ohio gubernatorial election was held on 10 October 1826, in order to elect the Governor of Ohio. National Republican candidate and former Acting Governor Allen Trimble defeated Democratic-Republican candidates Alexander Campbell, Benjamin Tappan and John Bigger.[1]
General election
[edit]On election day, 10 October 1826, National Republican candidate Allen Trimble won the election by a margin of 66,710 votes against his foremost opponent Democratic-Republican candidate Alexander Campbell, thereby gaining National Republican control over the office of Governor. Trimble was sworn in as the 10th Governor of Ohio on 19 December 1826.[2]
Results
[edit]Party | Candidate | Votes | % | |
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National Republican | Allen Trimble | 71,475 | 84.35% | |
Democratic-Republican | Alexander Campbell | 4,765 | 5.62% | |
Democratic-Republican | Benjamin Tappan | 4,192 | 4.95% | |
Democratic-Republican | John Bigger | 4,114 | 4.86% | |
Scattering | 187 | 0.22% | ||
Total votes | 84,733 | 100.00% | ||
National Republican gain from Democratic-Republican |
References
[edit]- ^ "Allen Trimble". National Governors Association. Retrieved 10 May 2024.
- ^ "OH Governor". ourcampaigns.com. 18 February 2005. Retrieved 10 May 2024.