1818 New Jersey gubernatorial election
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The 1818 New Jersey gubernatorial election was held on 29 October 1818 in order to elect the governor of New Jersey. Incumbent Democratic-Republican governor Isaac Halstead Williamson was re-elected by the New Jersey General Assembly as he ran unopposed.[1]
General election
[edit]On election day, 29 October 1818, incumbent Democratic-Republican governor Isaac Halstead Williamson was re-elected by the New Jersey General Assembly as he ran unopposed, thereby retaining Democratic-Republican control over the office of governor. Williamson was sworn in for his second term that same day.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Isaac Halstead Williamson (incumbent) | 52 | 100.00% | |
| Total votes | 52 | 100.00% | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Isaac Halstead Williamson". National Governors Association. Retrieved 21 September 2024.
- ^ "Williams-burnett to Williamson". politicalgraveyard.com. 8 March 2023. Retrieved 21 September 2024.
Categories:
- 1818 New Jersey elections
- 1818 in New Jersey
- New Jersey gubernatorial elections
- 1818 elections
- 1818 United States gubernatorial elections
- October 1818 events
- 1810s in New Jersey
- 1810s New Jersey elections
- 1818 elections in North America
- 1818 elections in the United States
- Government of New Jersey
- Indirect elections
- Single-candidate elections
- United States gubernatorial elections in the 1810s