1816 United States presidential election in Rhode Island

Main article: 1816 United States presidential election

1816 United States presidential election in Rhode Island

November 1 – December 4, 1816

Nominee James Monroe Party Democratic-Republican Home state Virginia Running mate Daniel D. Tompkins Electoral vote 4 Popular vote 1,236 Percentage 100.00%

President before election James Madison Democratic-Republican Elected President James Monroe Democratic-Republican

The 1816 United States presidential election in Rhode Island took place as part of the 1816 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.

Rhode Island voted for the Democratic-Republican candidate, James Monroe. Monroe won Rhode Island by a margin of 100.00%. Because the Federalist challenger in the nation, Rufus King, was not on the ballot.

Results

1816 United States presidential election in Rhode Island
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	James Monroe	1,236	100.00%	4
	Federalist	Rufus King (not on ballot)	—	—	0
Totals			1,236	100.0%	4

See also

• United States presidential elections in Rhode Island