1806 New Jersey gubernatorial election
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The 1806 New Jersey gubernatorial election was held on 31 October 1806 in order to elect the governor of New Jersey. Incumbent Democratic-Republican governor Joseph Bloomfield was unanimously re-elected by the New Jersey General Assembly as he ran unopposed.[1]
General election
[edit]On election day, 31 October 1806, incumbent Democratic-Republican governor Joseph Bloomfield was unanimously re-elected by the New Jersey General Assembly as he ran unopposed, thereby retaining Democratic-Republican control over the office of governor. Bloomfield was sworn in for his fifth term that same day.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Joseph Bloomfield (incumbent) | 53 | 100.00% | |
| Total votes | 53 | 100.00% | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Joseph Bloomfield". National Governors Association. Retrieved 2 July 2024.
- ^ "New Jersey 1806 Governor". elections.lib.tufts.edu. 11 January 2012. Retrieved 2 July 2024.
Categories:
- 1806 New Jersey elections
- 1806 in New Jersey
- New Jersey gubernatorial elections
- 1806 elections
- 1806 United States gubernatorial elections
- 1806 elections in North America
- 1806 elections in the United States
- Indirect elections
- Single-candidate elections
- October 1806 events
- 1800s New Jersey elections
- 1800s in New Jersey
- United States gubernatorial elections in the 1800s
- Government of New Jersey