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July 12

Question Related To Trigonometric Identities

If cosecά-sinα = a³ and secα-cosα = b³ then prove that a²b²(a² + b²)=1 — Preceding unsigned comment added by ManishRaichand (talk • contribs) 20:29, 12 July 2013 (UTC)[reply]

Welcome to Wikipedia. Your question appears to be a homework question. I apologize if this is a misinterpretation, but it is our aim here not to do people's homework for them, but to merely aid them in doing it themselves. Letting someone else do your homework does not help you learn nearly as much as doing it yourself. Please attempt to solve the problem or answer the question yourself first. If you need help with a specific part of your homework, feel free to tell us where you are stuck and ask for help. If you need help grasping the concept of a problem, by all means let us know. Dolphin (t) 12:12, 13 July 2013 (UTC)[reply]

As a hint, putting t=tan(α/2) will lead to (ab)^3=sinαcosα, a/b=cosα/sinα, from which it is easy to obtain the expression which is to equal unity.86.140.134.100 (talk) 21:49, 13 July 2013 (UTC)[reply]