User:Hamster-baldwin/sandbox

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$\frac{e}{on/off}=mc^2

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$e=\frac{m}{on/off}c^2

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To be clear; on/off is a literal referance to computational on switches divided by computational off switches.

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$e2=(\frac{\frac{m}{3}}{m_e}+\frac{\frac{m}{3}}{m_p}+\frac{\frac{m}{3}}{m_n})\hbar[\frac{h(\frac{c}{2\pi5.35317245x10^-11})^4}{c^2}]

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$m2=\frac{[(\frac{\frac{m}{3}}{m_e}+\frac{\frac{m}{3}}{m_p}+\frac{\frac{m}{3}}{m_n})2\frac{2Gm}{c^2}][\frac{h^2(\frac{c}{2\pi5.35317245x10^-11})^4}{c^2}]}{[\frac{G8\pi}{[\frac{1}{(2c^2)}]}]}

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$m2=\frac{[(\frac{\frac{m}{3}}{m_e}+\frac{\frac{m}{3}}{m_p}+\frac{\frac{m}{3}}{m_n})2\frac{2Gm}{c^2}][\frac{h^2(\frac{c}{2\pi9.26875894x10^-7})^4}{c^2}]}{[{G8\pi}]}

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$m2=(\frac{\frac{m}{3}}{m_e}+\frac{\frac{m}{3}}{m_p}+\frac{\frac{m}{3}}{m_n})\hbar[\frac{h(\frac{c}{2\pi9.26875894x10^-7})^4}{c^2}]

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Electrostatic acceleration of small masses;

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$f=ma

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Let l_p$ represent the Planck Mass, and cl_p$ represent c times the planck mass.

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$2c^2=(\frac{\frac{m}{3}}{m_e}+\frac{\frac{cl_p140.938613}{3}}{m_p}+\frac{\frac{cl_p140.938613}{3}}{m_n})\hbar[\frac{h(\frac{c}{2\pi5.35317245x10^-11})^4}{c^2}]

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$cl_p140.938613=0.00000306781079

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Let $m_p_na$ represent the acceleration of the protons and neutrons (for teleportation).

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$m_p_na=c\frac{\frac{2G(cl_p140.938613)}{c^2}}{[\frac{2Gm}{c^2}]}

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Teleportation; the electron masses contain two of the entire masses of the object.

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$m4=\frac{\frac{(\frac{\frac{m}{3}}{m_e}+\frac{\frac{c[\frac{\frac{2G(cl_p140.938613)}{c^2}}{[\frac{2Gm}{c^2}]}]}{3}}{m_p}+\frac{\frac{c[\frac{\frac{2G(cl_p140.938613)}{c^2}}{[\frac{2Gm}{c^2}]}]}{3}}{m_n})\hbar[\frac{h(\frac{c}{2\pi9.720723344x10^-12})^4}{c^2}]}{2c^2}}{m_e}

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$6=\frac{(\frac{1}{m_p}+\frac{1}{m_n})\hbar[\frac{h(\frac{c}{2\pi9.720723344x10^-12})^4}{c^2}]}{c^2}

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$e2=(m/3/m_e)/[1/(m_ec^2)/6]

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$Cpu Hz=\frac{c}{r\pi2}

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The Bohr Radius (r_0)$ of hydrogen 5.29177210903x10^-11$ meters

was modified (r_m)$ in this theory to 5.35317245x10^-11$ meters

because hydrogen didn't carry sufficent charge for computation.

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$ Duk-Ro

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I regret that I would be lying if I had said I had found a physical or technical solution to the Hubbert Peak, yet it was worth noting so I have done so.

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https://wiki.riteme.site/wiki/Hubbert\_peak\_theory

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Bradley William Busch

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