User:Dalpoin

In semiconductor, valance bands are well characterised by 3 Luttinger parameters. At Г-point in band structure, $p_{3/2}$ and $p_{1/2}$ orbitals form valance bands. But spin-orbit coupling splits six fold degeneracy into high energy 4-fold and lower energy 2-fold bands. Again 4-fold degeneracy is lifted into heavy- and light hole bands by phenomenological Hamiltonian by J. M. Luttinger.

Three valance band state

In the presence of spin-orbit interaction, total angular momentum should take part in. From the three valance band, l=1 and s=1/2 state generate six state of |j,m_j> as $|{3 \over 2},\pm {3 \over 2}>,|{3 \over 2},\pm {1 \over 2}>,|{1 \over 2},\pm {1 \over 2}>$

The spin-orbit interaction from the relativistic quantum mechanics, lowers the energy of j=1/2 states down.

Phenomenological Hamiltonian for the j=3/2 states

Phenomenological Hamiltonian in spherical approximation is written as

$H={{\hbar ^{2}} \over {2m_{0}}}[(\gamma _{1}+{{5} \over {2}}\gamma _{2})k^{2}-2\gamma _{2}(k\cdot J)^{2}]$

Phenomenological Luttinger parameters $\gamma _{i}$ are defined as

$\alpha =\gamma _{1}+{5 \over 2}\gamma _{2}$

and

$\beta =\gamma _{2}$

If we take k as k=ke_z, the Hamiltonian is diagonalized for j=3/2 states.

$E={{\hbar ^{2}K^{2}} \over {2m_{0}}}(\gamma _{1}+{{5} \over {2}}\gamma _{2}-2\gamma _{2}(km_{j})^{2})$

Two degeneated resulting eigenenergies are

$E_{hh}={{\hbar ^{2}k^{2}} \over {2m_{0}}}(\gamma _{1}-2\gamma _{2})$ for $m_{j}=\pm {3 \over 2}$

$E_{lh}={{\hbar ^{2}k^{2}} \over {2m_{0}}}(\gamma _{1}+2\gamma _{2})$ for $m_{j}=\pm {1 \over 2}$

$E_{hh}$ ($E_{lh}$) indicates heav-(light-) hole band energy. If we regard the electrons as nearly free electrons, the Luttinger parameters describe effective mass of electron in each bands.

Measurement of Luttinger parameters

Luttinger parameter can be measured by Hot-electron luminescence experiment.