1826 United States Senate election in Pennsylvania
(Redirected from United States Senate election in Pennsylvania, 1826)
| Elections in Pennsylvania |
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 Government |
The 1826 United States Senate election in Pennsylvania was held on December 12, 1826. Isaac D. Barnard was elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
[edit]The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on December 12, 1826, to elect a Senator to serve the term beginning on March 4, 1827. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Jacksonian | Isaac D. Barnard | 108 | 81.20 | |
| Jacksonian | Samuel D. Ingham | 11 | 8.27 | |
| Jacksonian | Joseph Hemphill | 5 | 3.76 | |
| Jacksonian | James Buchanan | 3 | 2.26 | |
| Jacksonian | Thomas Sergeant | 1 | 0.75 | |
| N/A | Not voting | 5 | 3.76 | |
| Totals | 133 | 100.00% | ||
References
[edit]- ^ a b "U.S. Senate Election - 12 December 1826" (PDF). Wilkes University. Retrieved December 21, 2012.