Seward Lake
| Seward Lake | |
|---|---|
  Seward Lake Location of Seward Lake within New York State | |
| Location | Otsego County, New York |
| Coordinates | 42°32′23″N 74°50′27″W / 42.53972°N 74.84083°W |
| Primary outflows | Schenevus Creek |
| Basin countries | United States |
| Surface area | 28 acres (11 ha) |
| Surface elevation | 1,237 ft (377 m)[1] |
| Settlements | Schenevus |
Seward Lake is a small lake in Otsego County, New York. It is located west of Schenevus. Seward Lake drains west via an unnamed stream into Schenevus Creek.
References
[edit]- ^ "Hudson Lake". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2018-03-12.