Sand Pond (New York)
Appearance
Sand Pond | |
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Location | Delaware County, New York |
Coordinates | 41°54′57″N 75°11′04″W / 41.9157905°N 75.1844678°W |
Type | Lake |
Surface area | 48 acres (0.075 sq mi) |
Surface elevation | 1,480 feet (450 m)[1] |
Settlements | French Woods |
Sand Pond is a small lake located south of the hamlet of French Woods in Delaware County, New York. The pond is also directly adjacent to French Woods Festival Of The Performing Arts. Sand Pond drains south via an unnamed creek that flows into Bouchoux Brook. Pierce Pond is located north of Sand Pond.
See also
[edit]References
[edit]- ^ "Sand Pond". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2018-09-25.