1793 Pennsylvania gubernatorial election
(Redirected from Pennsylvania gubernatorial election, 1793)
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 County Results Mifflin: 50-60% 60-70% 70-80% 80-90% 90-100% Muhlenberg: 50-60% 60-70% | ||||||||||||||||
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| Elections in Pennsylvania |
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 Government |
The 1793 Pennsylvania gubernatorial election occurred on October 8, 1793. Incumbent Democratic-Republican governor Thomas Mifflin sought re-election to another term, defeating Federalist candidate and U.S. Representative Frederick Muhlenberg. Muhlenberg won only two counties: York and Bedford. However, Mifflin's 2-1 vote margin was down from his 10-1 victory margin in the 1790 gubernatorial election.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Thomas Mifflin (incumbent) | 20,479 | 65.43 | |
| Federalist | Frederick Muhlenberg | 10,803 | 34.51 | |
| Independent | Alexander McDowell | 8 | 0.03 | |
| N/A | Others | 11 | 0.04 | |
| Total votes | 31,301 | 100.00 | ||
References
[edit]- ^ "Article II". Constitution of the Commonwealth of Pennsylvania - 1790 (PDF).
- ^ Tinkcom, Harry Marlin. 1950. The Republicans and Federalists in Pennsylvania: 1790-1801. Harrisburg: Pennsylvania Historical and Museum Commission, p. 138
- ^ "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
- ^ "Pennsylvania Gubernatorial Election Returns 1793". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.