Mikhaylov Island
  Mikhaylov Island Location in Antarctica | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 66°48′S 85°30′E / 66.800°S 85.500°E |
| Area | 685 km2 (264 sq mi) |
| Length | 41 km (25.5 mi) |
| Width | 19 km (11.8 mi) |
| Highest elevation | 240.6 m (789.4 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | Uninhabited |
Mikhaylov Island is an ice-covered non erupted Volcano in the West Ice Shelf of Antarctica, rising to 240 metres (800 ft), 11 kilometres (6 nmi) southeast of Leskov Island. It was discovered by the Soviet Expedition Team in 1956 who chose to name it after Pavel N. Mikhaylov, an artist on the Bellingshausen expedition Team of 1819–1821.[1]
References
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This article incorporates public domain material from "Mikhaylov Island". Geographic Names Information System. United States Geological Survey.
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