1959 Hawaii gubernatorial election
Appearance
(Redirected from Hawaii gubernatorial election, 1959)
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Quinn: 50–60% Burns: 50–60% | ||||||||||||||||||||
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Elections in Hawaii |
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The 1959 Hawaii gubernatorial election was Hawaii's first gubernatorial election. The election was held on July 28, 1959, one month after Hawaiians had voted for statehood in accordance with the Hawaii Admission Act[1][2] and one month before admission as the 50th state on August 21, 1959.[3]
In the election, the Republican candidate, Territorial Governor William F. Quinn, defeated the Democratic candidate, Territorial Delegate John A. Burns. Quinn won only the island of Oahu while Burns carried all other islands.[4] This was the last time until 2002 that a Republican was elected governor of Hawaii.
General election
[edit]Results
[edit]Party | Candidate | Votes | % | ±% | |
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Republican | William F. Quinn | 86,213 | 51.12 | ||
Democratic | John A. Burns | 82,074 | 48.66 | ||
Commonwealth | David Kihei | 375 | 0.22 | ||
Majority | 4,139 | 2.45 | |||
Turnout | 168,662 | ||||
Republican hold |
See also
[edit]- 1959 United States Senate elections in Hawaii
- 1959 United States House of Representatives election in Hawaii
- 1959 Hawaii Senate election
References
[edit]- ^ "Hawaii Statehood Admissions Act, 1959". Hawaii-nation.org. Retrieved February 15, 2013.
- ^ "USC 48 Ch 3, S. 3 HAWAII". United States House of Representatives. Archived from the original on December 15, 2012. Retrieved February 15, 2013.
- ^ "When Did Hawaii Become A State?". Mauihawaii.org. Archived from the original on May 20, 2013. Retrieved August 12, 2021.
- ^ a b "HI Governor Race – Jul 28, 1959". Our Campaigns. Retrieved February 15, 2013.