1850 Belgian general election
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(Redirected from Belgian general election, 1850)
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54 of the 108 seats in the Chamber of Representatives 55 seats needed for a majority | ||||||||||||||||||||||||||||||||||
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Partial general elections were held in Belgium on 11 June 1850.[1][2] In the Chamber of Representatives elections the result was a victory for the Liberal Party, who won 69 of the 108 seats.[2] Voter turnout was 69.1%, although only 40,435 people were eligible to vote.
Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.
Results
[edit]Chamber of Representatives
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Party | Votes | % | Seats | |||||
Won | Total | +/– | ||||||
Liberal Party | 15,320 | 54.80 | 32 | 69 | –14 | |||
Catholics | 11,618 | 41.56 | 22 | 39 | +14 | |||
Others | 1,016 | 3.63 | 0 | 0 | 0 | |||
Total | 27,954 | 100.00 | 54 | 108 | 0 | |||
Total votes | 27,954 | – | ||||||
Registered voters/turnout | 40,435 | 69.13 | ||||||
Source: Mackie & Rose,[3] Sternberger et al. |