From Wikipedia, the free encyclopedia
1888 Belgian general election|
|
|
|
First party
|
Second party
|
|
|
|
Leader
|
Auguste Beernaert
|
|
Party
|
Catholic
|
Liberal
|
Leader since
|
Candidate for PM
|
|
Seats before
|
98 seats
|
40 seats
|
Seats won
|
66
|
3
|
Seats after
|
98
|
40
|
Seat change
|
|
|
Popular vote
|
31,273
|
19,967
|
Percentage
|
58.44%
|
37.31%
|
|
|
Partial general elections were held in Belgium on 12 June 1888.[1][2] The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate.[2]
Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.
Chamber of Representatives
[edit]
|
---|
Party | Votes | % | Seats |
---|
Won | Total | +/– |
---|
| Catholic Party | 31,273 | 58.44 | 66 | 98 | 0 |
| Liberal Party | 19,967 | 37.31 | 3 | 40 | 0 |
| Others | 2,277 | 4.25 | 0 | 0 | New |
Total | 53,517 | 100.00 | 69 | 138 | 0 |
|
Total votes | 53,517 | – | |
---|
Registered voters/turnout | 73,276 | 73.03 | |
---|
Source: Mackie & Rose,[3] Sternberger et al. |
- ^ Codebook Constituency-level Elections Archive, 2003
- ^ a b Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
- ^ Thomas T. Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51