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2005 tennis event results
Jiří Novák was the defending champion, but did not participate.
Wesley Moodie won the title, defeating Mario Ančić in the final 1–6, 7–6(9–7), 6–4.[1]
All seeds receive a bye into the second round.
Top half[edit]
Section 1[edit]
Section 2[edit]
Bottom half[edit]
Section 3[edit]
Section 4[edit]
References[edit]
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Grand Slam events | |
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ATP Masters Series | |
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ATP International Series Gold | |
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ATP International Series |
- Adelaide (S, D)
- Doha (S, D)
- Chennai (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Viña del Mar (S, D)
- Delray Beach (S, D)
- Milan (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Buenos Aires (S, D)
- Bahia (S, D)
- Scottsdale (S, D)
- Valencia (S, D)
- Casablanca (S, D)
- Houston (S, D)
- Estoril (S, D)
- Munich (S, D)
- St. Pölten (S, D)
- Düsseldorf
- Halle (S, D)
- London/Queen's Club (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Indianapolis (S, D)
- Amersfoort (S, D)
- Umag (S, D)
- Los Angeles (S, D)
- Sopot (S, D)
- Washington (S, D)
- New Haven (S, D)
- Beijing (S, D)
- Bucharest (S, D)
- Palermo (S, D)
- Ho Chi Minh City (S, D)
- Bangkok (S, D)
- Metz (S, D)
- Stockholm (S, D)
- Basel (S, D)
- Lyon (S, D)
- St. Petersburg (S, D)
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Team events | |
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