1926 Maryland Attorney General election
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 County results Robinson: 50–60% 60–70% Broening: 50–60% 60–70% | |||||||||||||||||
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| Elections in Maryland |
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 Government |
The 1926 Maryland attorney general election was held on 2 November 1926 in order to elect the attorney general of Maryland. Democratic nominee and incumbent attorney general Thomas H. Robinson defeated Republican nominee and former Mayor of Baltimore William Frederick Broening and Socialist nominee John A. Orman.[1]
General election
[edit]On election day, 2 November 1926, Democratic nominee Thomas H. Robinson won re-election by a margin of 36,282 votes against his foremost opponent Republican nominee William Frederick Broening, thereby retaining Democratic control over the office of attorney general. Robinson was sworn in for his second term on 3 January 1927.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Thomas H. Robinson (incumbent) | 184,337 | 54.97 | |
| Republican | William Frederick Broening | 148,055 | 44.15 | |
| Socialist | John A. Orman | 2,951 | 0.88 | |
| Total votes | 335,343 | 100.00 | ||
| Democratic hold | ||||
References
[edit]- ^ "1926 Attorney General General Election Results - Maryland". uselectionatlas.org. February 29, 2016. Retrieved October 22, 2024.
- ^ "MD Attorney General". ourcampaigns.com. May 27, 2020. Retrieved October 22, 2024.
