Template:User wikipedia/Oversighter
Appearance
(Redirected from Template:User wikipedia/oversight)
![]() | This user is an oversighter on the English Wikipedia. (verify) |
Template parameters
Usage
Markup | Renders as | ||
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{{User wikipedia/Oversighter}} |
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{{User wikipedia/Oversighter|[[Russian Wikipedia]]|lang_code=ru}} |
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{{User wikipedia/Oversighter|RFA=WP:USER}} |
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