Talk:Young's convolution inequality
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Should we consider replacing with for any locally compact abelian group ? Given the fact that Young's inequality is used not only for but also and sometimes even , I think the theorem would be better formulated with a higher level of generality than it currently is. — Preceding unsigned comment added by 79.68.238.151 (talk) 12:22, 19 August 2017 (UTC)
and
[edit]I think it should be mentioned in the article that, let where is the space of continue functions that vanish at infinity (note that the dual space of is , where is the dual index of ; I believe that for any whose measure and topology cooperate well), then we actually have , implying (see here). For and we only know that the convolution is continuous and bounded (take to be constant, for example).
This link may be relevant, but I'm not sure. 129.104.241.214 (talk) 22:11, 15 February 2024 (UTC)
r and its conjugate exponent
[edit]It's confusing that the symbol r is used twice, both for an exponent and for its conjugate exponent. In the "duality formulation" (the second in the article), the r that appears there is the conjugate exponent of the r in the first inequality. I propose changing the second r to s. Ulrigo (talk) 14:36, 20 March 2024 (UTC)