Talk:.41 Short
This is the talk page for discussing improvements to the .41 Short article. This is not a forum for general discussion of the article's subject. |
Article policies
|
Find sources: Google (books · news · scholar · free images · WP refs) · FENS · JSTOR · TWL |
![]() | This article is rated Stub-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | ||||||||||||||||||||
|
Comments
[edit]Why was this page removed?
- Please remember to sign your posts. Kartano (talk) 03:26, 2 February 2010 (UTC)
Image request
[edit]I've requested permission to use an image of the .41 short from the Ammo One online store. Hopefully I'll hear back soon from the author with permission to use the image. Kartano (talk) 03:26, 2 February 2010 (UTC)
Anon: the 52 foot-pounds force in the intro should really be changed 52 foot-pounds energy. joules is the metric equivalent so thats fine —Preceding unsigned comment added by 128.2.160.174 (talk) 00:53, 21 February 2010 (UTC)
Duplicate Article?
[edit]I found this in Wikipedia
https://wiki.riteme.site/wiki/.41_rimfire
Are these the same? Jokem (talk) 03:55, 9 February 2019 (UTC)
Arithmetic error?
[edit]"According to Cartridges of the World, the .41 Rimfire consisted of a 130 grain (8.4 g) lead bullet propelled by 13 grains (0.8 g) of black powder in its original load. The round produced a muzzle velocity of 425 feet per second (130 m/s) and a muzzle energy of 52 foot-pounds force (71 J). However, more recently firearms writer Holt Bodinson has disputed these findings. He states that his testing showed the 130 grain bullet traveled at 685 feet per second (209 m/s) so producing 111 foot-pounds force (150 J) of energy - a significant difference in ballistic energy from the earlier tests. The difference in findings can potentially be attributed to variances in the specific ammunition fired or measuring equipment used."
The equation for Kinetic Energy is 1/2 mv^2.
For the first calculation of the energy: 1/2 x 0.0084 kg x (130 m/s)^2 = 70.98 Joules ... so "71 J" is correct.
For the second calculation of the energy: 1/2 x 0.0084 kg x (209 m/s)^2 = 183.46 Joules ... so "150 J" is incorrect.
[I do not have access to the original data to know whether the result (150 J) is wrong or the stated velocity (209 m/s) is wrong.]
Atpollard (talk) 21:20, 18 January 2024 (UTC)
- I found the error. In the source article, the "685 feet per second (209 m/s)" was for the .38 S&W and not the .41 Short. The correct velocity from the article cited should be 621 fps (189 m/s) which yields 111 ft-lbs (150 J). Atpollard (talk) 13:02, 25 January 2024 (UTC)