Verschaffeltia
Appearance
(Redirected from Stilt palm)
Verschaffeltia | |
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Scientific classification ![]() | |
Kingdom: | Plantae |
Clade: | Tracheophytes |
Clade: | Angiosperms |
Clade: | Monocots |
Clade: | Commelinids |
Order: | Arecales |
Family: | Arecaceae |
Subfamily: | Arecoideae |
Tribe: | Areceae |
Subtribe: | Verschaffeltiinae |
Genus: | Verschaffeltia H.Wendl. |
Species: | V. splendida
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Binomial name | |
Verschaffeltia splendida H.A. Wendl.
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Verschaffeltia splendida ("Latanier Latte" or stilt palm[2]) is a species of flowering plant in the family Arecaceae. It is the only species in the genus Verschaffeltia.[citation needed]
It is found only in Seychelles where it is threatened by habitat loss. The name comes from the Belgian Ambroise Verschaffelt.
Description
[edit]This species can be distinguished from all other palm species of the Seychelles, by its characteristic stilt-roots.
The slender trunk has a very hard outer covering. The leaves are initially unbroken, and those of the young plants have black spines on their stalks. They bear green-brown fruits with unique seeds.
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The stilt-roots of this species
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The black spines that cover the stem and leaves of young plants
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The unbroken young leaves
References
[edit]- ^ Ismail, S.; Huber, M.J.; Mougal, J. (2011). "Verschaffeltia splendida". IUCN Red List of Threatened Species. 2011: e.T38722A10145395. doi:10.2305/IUCN.UK.2011-2.RLTS.T38722A10145395.en. Retrieved 14 November 2021.
- ^ Palmpedia