Asclepias amplexicaulis
Appearance
(Redirected from Sand milkweed)
Asclepias amplexicaulis | |
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Scientific classification | |
Kingdom: | Plantae |
Clade: | Tracheophytes |
Clade: | Angiosperms |
Clade: | Eudicots |
Clade: | Asterids |
Order: | Gentianales |
Family: | Apocynaceae |
Genus: | Asclepias |
Species: | A. amplexicaulis
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Binomial name | |
Asclepias amplexicaulis |
Asclepias amplexicaulis, the blunt-leaved milkweed, clasping milkweed, or sand milkweed, is a species of flowering plant in the subfamily Asclepiadoideae (Apocynaceae).[1][2] It is endemic to the United States, where it is mostly found east of the Great Plains.[3] It grows in dry prairies, savannas, open woods, and fallow fields, usually in sandy soil.[2][4][5]
Description
[edit]It grows 1–3 ft (0.30–0.91 m) high and produces flowers in the summer.[4]
This plant was eaten as food historically. However, it contains a poison dangerous to humans and livestock, so caution must be used if ingesting this plant.[6]
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In flower at Nachusa Grasslands in Illinois
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Line drawing
References
[edit]- ^ NRCS. "Asclepias amplexicaulis". PLANTS Database. United States Department of Agriculture (USDA).
- ^ a b Wilhelm, Gerould; Rericha, Laura (2017). Flora of the Chicago Region: A Floristic and Ecological Synthesis. Indiana Academy of Sciences.
- ^ "Asclepias amplexicaulis". County-level distribution map from the North American Plant Atlas (NAPA). Biota of North America Program (BONAP). 2014. Retrieved 24 January 2017.
- ^ a b "Asclepias amplexicaulis". Connecticut Plants. Connecticut Botanical Society. 2015.
- ^ Haddock, Mike (2018). "Blunt-leaf milkweed". Kansas Wildflowers and Grasses. Retrieved July 20, 2018.
- ^ "Asclepias amplexicaulis". Illinois Prairie. MuseumLink Illinois, Illinois State Museum Society. 2000.
External links
[edit]- Media related to Asclepias amplexicaulis at Wikimedia Commons