Jump to content

Lupul (Tazlău)

Coordinates: 46°22′42″N 26°42′57″E / 46.37833°N 26.71583°E / 46.37833; 26.71583
From Wikipedia, the free encyclopedia
(Redirected from Lupul River (Tazlau))
Lupul
Lupul (Tazlău) is located in Romania
Lupul (Tazlău)
Location
CountryRomania
CountiesBacău County
VillagesAlbele, Poiana
Physical characteristics
MouthTazlău
 • location
Poiana
 • coordinates
46°22′42″N 26°42′57″E / 46.37833°N 26.71583°E / 46.37833; 26.71583
 • elevation
230 m (750 ft)
Length9 km (5.6 mi)
Basin size17 km2 (6.6 sq mi)
Basin features
ProgressionTazlăuTrotușSiretDanubeBlack Sea

The Lupul is a right tributary of the river Tazlău in Romania.[1][2] It flows into the Tazlău in Poiana. Its length is 9 km (5.6 mi) and its basin size is 17 km2 (6.6 sq mi).[1]

References

[edit]
  1. ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 410. OCLC 895459847. River code: XII.1.69.33.18
  2. ^ Ovidiu Gabor - "Economic Mechanism in Water Management" (PDF). Archived from the original (PDF) on 5 March 2009., map page 10