Lambertia fairallii
Appearance
(Redirected from Fairall's honey-suckle)
Lambertia fairallii | |
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Scientific classification ![]() | |
Kingdom: | Plantae |
Clade: | Tracheophytes |
Clade: | Angiosperms |
Clade: | Eudicots |
Order: | Proteales |
Family: | Proteaceae |
Genus: | Lambertia |
Species: | L. fairallii
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Binomial name | |
Lambertia fairallii |
Lambertia fairallii, commonly known as Fairall's honeysuckle, is a shrub which is endemic to the south-west of Western Australia.[1]
The species was formally described in 1983 by botanist Greg Keighery.[1][2]
Description
[edit]A description of L. fairallii is given in Florabase.[3]
References
[edit]- ^ a b c "Lambertia fairallii". Australian Plant Name Index (APNI), IBIS database. Centre for Plant Biodiversity Research, Australian Government, Canberra. Retrieved 31 January 2015.
- ^ a b Keighery, G.J. 1983. New species from the Stirling Range of Western Australia. Botanische Jahrbücher für Systematik, Pflanzengeschichte und Pflanzengeographie 104(2): 180, fig. 3
- ^ "Florabase: Lambertia fairallii". Western Australian Herbarium. Retrieved 31 January 2015. Retrieved 26 March 2018.