Jump to content

Der Abi Saeed

From Wikipedia, the free encyclopedia
(Redirected from Deir Abu Sa'id)

Der Abi Saeed
دير أبي سعيد
City
Der Abi Saeed is located in Jordan
Der Abi Saeed
Der Abi Saeed
Coordinates: 32°30′9″N 35°41′32″E / 32.50250°N 35.69222°E / 32.50250; 35.69222
Grid position214/212
CountryJordan
ProvinceIrbid Governorate
Government
 • TypeMunicipality
Population
 (2015)[1]
 • Total
29,590
Time zoneGMT +2
 • Summer (DST)+3
Area code+(962)2

Der Abi Saeed (Arabic: دير أبي سعيد) is a city in Irbid Governorate in Jordan. It is named after a historic Christian chapel ('Der' in Arabic) in the place where the city is built. The city gained importance in the early 20th century after the formation of a self-governing body following the fall of the Ottoman Empire. Der Abi Saeed is the administrative center of the Koura Department, one of the nine departments of Irbid Governorate.

Geography

[edit]

The city is located in the Jordanian part of the Houran Plateau, about 25 km (16 mi) to the southwest of the city of Irbid in the province of Irbid Governorate, and about 83 km (52 mi) to the north from Jordan's capital Amman.

The historic mosque of Der Abi Saeed

History

[edit]

In 1838 Der Abi Saeed's inhabitants were predominantly Sunni Muslims.[2]

The Jordanian census of 1961 found 1,927 inhabitants in Deir Abu Sa'id.[3]

Districts

[edit]

The municipality of Der Abi Saeed includes eight districts:

References

[edit]
  1. ^ "The General Census - 2015" (PDF). Department of Population Statistics.
  2. ^ Smith, in Robinson and Smith, 1841, vol 3, 2nd appendix, p. 165
  3. ^ Government of Jordan, Department of Statistics, 1964, p. 20

Bibliography

[edit]
[edit]