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1948 U.S. National Championships – Women's singles

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Women's singles
1948 U.S. National Championships
Final
ChampionUnited States Margaret Osborne duPont[1]
Runner-upUnited States Louise Brough
Score4–6, 6–4, 15–13
Events
Singles men women
Doubles men women
← 1947 · U.S. National Championships · 1949 →

Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the women's singles tennis title at the 1948 U.S. National Championships.[1][2]

Seeds

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The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]

  1. United States Louise Brough (finalist)
  2. United States Doris Hart (quarterfinals)
  3. United States Margaret Osborne duPont (champion)
  4. United States Pat Canning Todd (semifinals)
  5. United States Shirley Fry (third round)
  6. United States Beverly Baker (quarterfinals)
  7. United States Gussy Moran (semifinals)

Draw

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Key

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Final eight

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Quarterfinals Semifinals Finals
               
7 United States Gussy Moran 6 6
2 United States Doris Hart 4 4
7 United States Gussy Moran 8 4
3 United States Margaret Osborne duPont 10 6
3 United States Margaret Osborne duPont 1 6 6
United States Beverly Baker 6 2 0
3 United States Margaret Osborne duPont 4 6 15
1 United States Louise Brough 6 4 13
1 United States Louise Brough 6 6
United States Virginia Kovacs 3 2
1 United States Louise Brough 6 6
4 United States Pat Canning Todd 3 3
4 United States Pat Canning Todd 6 6
United States Madge Vosters 3 1

References

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  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
  2. ^ "Exciting Game for Tennis Title". The Cairns Post. Qld. September 21, 1948. p. 1 – via National Library of Australia.
  3. ^ G.P. Hughes, ed. (1949). Dunlop Lawn Tennis Annual and Almanack 1949. London: Ed. J. Burrow & Co. Ltd. pp. 159–164.
Preceded by Grand Slam women's singles Succeeded by