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1938 French Championships (tennis)

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(Redirected from 1938 French Amateur)
1938 French Championships
Date2–11 June 1938
Edition43rd
Category14th Grand Slam (ITF)
SurfaceClay
LocationParis (XVIe), France
VenueStade Roland Garros
Champions
Men's singles
United States Don Budge[1]
Women's singles
France Simonne Mathieu[2]
Men's doubles
France Bernard Destremau / France Yvon Petra
Women's doubles
France Simonne Mathieu / United Kingdom Billie Yorke
Mixed doubles
France Simonne Mathieu / Kingdom of Yugoslavia Dragutin Mitić
← 1937 · French Championships · 1939 →

The 1938 French Championships (now known as the French Open) was a tennis tournament that took place on the outdoor clay courts at the Stade Roland-Garros in Paris, France. The tournament ran from 2 June until 11 June. It was the 43rd staging of the French Championships and the second Grand Slam tournament of the year.

Finals

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Men's singles

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United States Don Budge defeated Czechoslovakia Roderich Menzel 6–3, 6–2, 6–4

Women's singles

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France Simonne Mathieu defeated France Nelly Adamson 6–0, 6–3

Men's doubles

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France Bernard Destremau / France Yvon Petra defeated United States Don Budge / United States Gene Mako 3–6, 6–3, 9–7, 6–1

Women's doubles

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France Simonne Mathieu / United Kingdom Billie Yorke defeated France Arlette Halff / France Nelly Landry 6–3, 6–3

Mixed doubles

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France Simonne Mathieu / Kingdom of Yugoslavia Dragutin Mitić defeated Australia Nancye Wynne Bolton / France Christian Boussus 2–6, 6–3, 6–4

References

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  1. ^ "Roland-Garros 1938 (Grand Slam) - Men singles" (PDF). Fédération Française de Tennis (FFT). Archived from the original (PDF) on 2013-12-03.
  2. ^ "Roland-Garros 1938 (Grand Slam) - Women singles" (PDF). Fédération Française de Tennis (FFT). Archived from the original (PDF) on 2013-12-03. Retrieved 2013-11-30.
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Preceded by Grand Slams Succeeded by