Jump to content

1912 Paris–Roubaix

From Wikipedia, the free encyclopedia
(Redirected from 1912 Paris-Roubaix)

1912 Paris–Roubaix
Race details
Dates7 April 1912
Stages1
Distance266 km (165.3 mi)
Winning time8h 30' 00"
Results
  Winner  Charles Crupelandt (FRA)
  Second  Gustave Garrigou (FRA)
  Third  Maurice Léturgie (FRA)
← 1911
1913 →

The 1912 Paris–Roubaix was the 17th edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 7 April 1912 and stretched 266 km (165 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Charles Crupelandt from France.[2]

Results

[edit]
Final results (1–10)[2]
Rank Cyclist Time
1  Charles Crupelandt (FRA) 8h 30' 00″
2  Gustave Garrigou (FRA) +0' 00″
3  Maurice Léturgie (FRA) +0' 00″
4  Octave Lapize (FRA) +0' 00″
5  Odiel Defraye (BEL) +0' 00″
6  Jules Masselis (BEL) +0' 00″
7  Charles Deruyter (BEL) +0' 00″
8  Joseph Van Daele (BEL) +6' 00″
9  Eugène Platteau (BEL) +6' 00″
10  Paul Deman (BEL) +6' 00″

References

[edit]
  1. ^ "17th Paris – Roubaix, 1912". bikeraceinfo. Retrieved 5 March 2015.
  2. ^ a b "1912  » 17th Paris – Roubaix". ProCyclingStats. Retrieved 5 March 2015.