1881 Wimbledon Championship
Appearance
(Redirected from 1881 Wimbledon Championships)
1881 Wimbledon Championship | |
---|---|
Date | 2 – 13 July |
Edition | 5th |
Category | Grand Slam |
Surface | Grass |
Location | Worple Road SW19, Wimbledon, London, United Kingdom |
Venue | All England Croquet and Lawn Tennis Club |
Champions | |
Singles | |
William Renshaw |
The 1881 Wimbledon Championships took place on the outdoor grass courts at the All England Lawn Tennis and Croquet Club in Wimbledon, London, United Kingdom. The tournament ran from 2 to 13 July.[1] It was the 5th edition of the Wimbledon Championships, and the first Grand Slam tennis event of 1881.[2] The defending champion John Hartley lost in straight sets in the final to challenger William Renshaw, who defeated Hartley in 37 minutes, 6–0, 6–1, 6–1.[3][2] The result is said to have been influenced by Hartley suffering from an attack of 'English cholera'.[2]
Singles
[edit]Final
[edit]William Renshaw defeated John Hartley, 6–0, 6–1, 6–1 [3]
All Comers' Final
[edit]William Renshaw defeated Richard Richardson, 6–4, 6–2, 6–3 [2]
References
[edit]- ^ 2010 Wimbledon Compendium, by Alan Little (The All England Lawn Tennis and Croquet Club, Wimbledon, London)
- ^ a b c d 100 Years of Wimbledon, by Lance Tingay (Guinness Superlatives, 1977)
- ^ a b "Gentlemen's Singles Finals 1877-2016". wimbledon.com. Wimbledon Championships. Retrieved 29 June 2017.